23492u undergoes alpha decay. what is the atomic number of the resulting element. express your answer numerically as an integer.

Question

Sophie Le

Chemistry

3 December, 18:47

23492u undergoes alpha decay. what is the atomic number of the resulting element. express your answer numerically as an integer.

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Answers (1)

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Angeline Hudson · Answer 1

Answer is: mass number of element is 230.

Alpha particle is nucleus of a helium-4 atom, which is made of two protons and two neutrons.

²³ ⁴U → ²³⁰X + α (alpha particle).

Alpha decay is radioactive decay in which an atomic nucleus emits an alpha particle (helium nucleus) and transforms into an atom with an atomic number that is reduced by two and mass number that is reduced by four.