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11 May, 01:23

A gas sample has a temperature of 22c with an unknown volume. The same gas has a volume of 456 mL when the temperature is 86c with no change in the pressure or amount of gas. What was the initial volume in millimeters oh the gas

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  1. 11 May, 01:28
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    V₁ = 374.71 mL

    Explanation:

    Given dа ta:

    Initial volume of gas=?

    Initial temperature = 22°C

    Final temperature = 86°C

    Final volume = 456 mL

    Solution:

    Initial temperature = 22°C (22+273 = 295 k)

    Final temperature = 86°C (86+273 = 359 k)

    The given problem will be solve through the Charles Law.

    According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

    Mathematical expression:

    V₁/T₁ = V₂/T₂

    V₁ = Initial volume

    T₁ = Initial temperature

    V₂ = Final volume

    T₂ = Final temperature

    Now we will put the values in formula.

    V₁/T₁ = V₂/T₂

    V₁ = V₂T₁ / T₂

    V₁ = 456 mL * 295 K / 359 k

    V₁ = 134520 mL. K / 359 k

    V₁ = 374.71 mL
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