How many mL of a. 132 M aqueous solution of sodium chloride, NaCl, must be taken to obtain 3.59 grams of the salt?

465mL

Explanation:

Volume of a solution, V = Mass of substance, m / (Molarity of the solution of the substance, M * molar mass of the substance, M. m)

Given in the question,

M=.132M

M. m=23+35.5 = 58.5g/mol

m=3.59g

V = 3.59 / (.132*58.5)

V = 0.465L

Volume in mL = volume in L * 1000

= 0.465 * 1000 = 465mL

Therefore, 465mL of a. 132M aqueous solution of sodium chloride, NaCl, must be taken to obtain 3.59 grams of the salt