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25 April, 02:45

What is the molarity of a solution if 300.0 ml of it contains 16.8 g of kno3? [formula weight: kno3, 101.11 amu]?

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  1. 25 April, 02:48
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    The molarity is count by dividing the mole of the solute within 1 liter of solvent. In this case, the KNO3 is 16.8g with 101.11 g/mol molar mass. Then we need to find the mol first. The calculation would be: 16.8g / (101.11g/mol) = 0.0166 mol.

    Then the molarity would be: 0.0166mol / 0.3l = 0.0498 = 0.0553 M
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