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23 December, 16:03

A surgeon needs 9 liters of a 3% saline solution. She has a 1% solution and a 10% solution available. How many liters of the 1% solution and how many liters of the 10% solution should she mix to make the 3% solution?

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Answers (2)
  1. 23 December, 16:05
    0
    7 L of the 1% solution

    2 L of the 10% solution
  2. 23 December, 16:30
    0
    7 L of the 1% solution and 2 L of the 10% solution should she mix to make the 9 L of 3% solution.

    Explanation:

    Let the volume of 1% solution be mixed to make 3% solution = a L

    Let the volume of 10% solution be mixed to make 3% solution = b L

    Given, Volume of 3% solution = 9 L

    Thus, a + b = 9 ... 1

    Also,

    Applying C₁V₁ + C₂V₂ = C₃V₃

    Where,

    C₁ is the concentration of the 1% liquid

    C₂ is the concentration of the 10% liquid

    C₃ is the concentration of the 3% liquid

    V₁ is the volume of the 1% liquid (a L)

    V₂ is the volume of the 10% liquid (b L)

    V₃ is the volume of the 3% liquid (9 L)

    So,

    1*a + 10*b = 9*3

    a + 10b = 27 ... 2

    Solving equation 1 and 2, we get:

    a = 7 L and b = 2 L

    Thus, 7 L of the 1% solution and 2 L of the 10% solution should she mix to make the 3% solution.
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