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9 March, 20:51

Some over-the-counter antacids contain aluminum hydroxide, whereas others contain calcium carbonate. If a tablet contains 750 mg of Al (OH) 3, and another contains 750 mg of CaCO3, which consumes the greater mass of HCl?

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  1. 9 March, 21:04
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    AL (OH) 3 consumes greter mass of HCl.

    Explanation:

    Equation of the reaction

    CaCO3 (s) + HCl (aq) - -> CaCl2 (aq) + CO2 (g) + H2O (g)

    Mass of CaCO3 = 750 mg

    = 0.75 g

    Molar mass = 40 + 12 + (16*3)

    = 100 g/mol.

    Since 1 mole of CaCO3 reactes with 1 mole of HCl to form 1 mole of CaCl2.

    Number of moles = mass/molar mass

    = 0.75/100

    = 0.0075 moles of CaCO3

    = 0.0075 moles of HCl

    Molar mass of HCl = 1 + 35.5

    = 36.5 g/mol

    Mass of HCl consumed = moles*molar mass

    = 0.0075*36.5

    = 0.27 g of HCl

    Equation of reaction

    Al (OH) 3 (aq) + 3HCl (aq) - -> AlCl3 (aq) + 3H2O (g)

    Mass of Al (OH) 3 = 750 mg

    = 0.75 g

    Molar mass = 27 + (1 + 16) * 3

    = 78 g/mol.

    Since 1 mole of Al (OH) 3 reactes with 3 mole of HCl to form 1 mole of AlCl3.

    Number of moles = mass/molar mass

    = 0.75/78

    = 0.0096 moles of Al (OH) 3

    = 0.0096*3

    = 0.02885 moles of HCl

    Molar mass of HCl = 1 + 35.5

    = 36.5 g/mol

    Mass of HCl consumed = moles*molar mass

    = 0.02885*36.5

    = 1.05 g of HCl

    Therefore, Al (OH) 3 consumes greater mass of HCl.
  2. 9 March, 21:09
    0
    750 mg of Al (OH) 3 consumes greater mass of HCl

    Explanation:

    Equation of reaction between CaCO3 and HCl:

    CaCO3 + 2HCl = CaCl2 + CO2 + H2O

    1 mole (100g) of CaCO3 consumes 2 moles (73g) of HCl

    750mg (0.75g) of CaCO3 will consume 0.75*73/100 = 0.5475g of HCl

    Equation of reaction between Al (OH) 3 and HCl:

    Al (OH) 3 + 3HCl = AlCl3 + 3H2O

    1 mole (78g) of Al (OH) 3 consumes 3 mole (109.5g) of HCl

    750mg (0.75g) of CaCO3 will consume 0.75*109.5/78 = 1.0529g of HCl

    750mg of CaCO3 consumes 0.5475g of HCl while 750mg of Al (OH) 3 consumes 1.0529g of HCl
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