4.2g of sodium bicarbonate is equivalent to how many moles of sodium bicarbonate

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Braiden

Chemistry

12 September, 08:31

4.2g of sodium bicarbonate is equivalent to how many moles of sodium bicarbonate

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Walker Leach · Answer 1

The mass of one mole of sodium bicarbonate (aka NaHCO3) is equal to 1 * 22.99g/mol + 1 * 1.00g/mol + 1 * 12.01g/mol + 3 * 16.00g/mol = 83.91g/mol. From this, we can convert 4.2g of NaHCO3 to moles by dividing by 83.91g/mol, to get 0.050 moles of sodium bicarbonate.