A flexible vessel contains 43L of gas where the pressure is 1.3 atm. What will the volume be when the pressure is 0.61 atm, the temperature remaining constant?

91.64L

Explanation:

Step 1:

Data obtained from the question.

This includes the following:

Initial volume (V1) = 43L

Initial pressure (P1) = 1.3 atm

Final volume (V2) = ... ?

Final pressure (P2) = 0.61 atm

Step 2:

Determination of the final volume.

To solve for the final volume, we'll apply the Boyle's law equation since the temperature is constant. The final volume is obtained as follow:

P1V1 = P2V2

1.3 x 43 = 0.61 x V2

Divide both side by 0.61

V2 = (1.3 x 43) / 0.61

V2 = 91.64L

Therefore, the new volume is 91.64L