An object was measured by a worker as 17.4cm long, however, the manufacturer specifications list the length of the object at 17.9cm. What is the percent error in the workers measurements? (In chemistry)

Percent error = 2.8

Explanation:

Given data;

Actual value = 17.9 cm

Measured value = 17.4 cm

Percent error = ?

Solution:

Formula:

Percent error = [actual value - measured value / actual value] * 100

Now we will put the values in formula:

Percent error = [17.9 cm - 17.4 cm / 17.9 cm] * 100

Percent error = [0.5 cm / 17.9 cm] * 100

Percent error = 0.028 * 100

Percent error = 2.8