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26 September, 16:25

What is the molarity of ZnCl2 that forms when 25.0 g of zinc completely reacts with CuCl2 according to the following reaction? Assume a final volume of 275 mL. Tro, Nivaldo J ... Chemistry (p. 204). Pearson Education. Kindle Edition.

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  1. 26 September, 16:27
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    The molarity of ZnCl2 is 1.39 M

    Explanation:

    Step 1: The balanced equation

    Z n (s) + C u C l 2 (a q) → Z n C l 2 (a q) + C u (s)

    Step 2: Given data

    The mass of zinc = 25.0 g

    The volume of solution = 275 mL

    Step 3: Calculate moles of Zinc

    Moles of Zn = mass of Zn / Molar mass of Zn

    Moles of Zn = 25.0 grams / 65.38 Molar mass

    Moles of Zn = 0.382 moles

    Step 4: Calculate moles of ZnCl2

    For 1 mole of Zn consumed, we need 1 mole of ZnCl2

    For 0.382 moles of Zn we produce 0.382 moles of ZnCl2

    Step 5: Calculate the molarity of ZnCl2

    Molarity = Moles / Volume

    Molarity = 0.382 moles / 0.275 L

    Molarity = 1.39 M

    The molarity of ZnCl2 is 1.39 M
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