How many grams of ca are needed to react completely with 2.20 L of a 4.50 m hcl solution

Ca + 2HCl = CaCl₂ + H₂

c=4.50 mol/l

v=2.20 l

n (HCl) = cv

m (Ca) / M (Ca) = n (HCl) / 2

m (Ca) = M (Ca) cv/2

m (Ca) = 40g/mol·4.50mol/l·2.20l/2=198 g

198 grams of Ca are needed