Ask Question
19 November, 14:02

Calculate the theoretical yield if 100.0 g p4o10 react with 200.0 g h2o

+5
Answers (1)
  1. 19 November, 14:21
    0
    The reaction of Phosphorous Pentaoxide with water yield Phosphoric Acid as shown below,

    P₄O₁₀ + 6 H₂O → 4 H₃PO₄

    According to balance equation,

    283.88 g (1 mole) P₄O₁₀ requires = 108 g (6 mole) of H₂O

    So,

    100 g P₄O₁₀ will require = X g of H₂O

    Solving for X,

    X = (100 g * 108 g) : 283.88 g

    X = 38.04 g of H₂O

    So, 100 g P₄O₁₀ requires 38.04 g of H₂O, while we are provided with 200 g of H₂O which means that water is in excess and P₄O₁₀ is limiting reagent. Therefore, P₄O₁₀ will control the yield of H₃PO₄. So,

    As,

    283.88 g (1 mole) P₄O₁₀ produced = 391.96 g (4 mole) of H₃PO₄

    So,

    100 g P₄O₁₀ will produce = X g of H₃PO₄

    Solving for X,

    X = (100 g * 391.96 g) : 283.88 g

    X = 138.07 g of H₃PO₄

    Result:

    Theoretical Yield of this reaction is 138.07 g.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Calculate the theoretical yield if 100.0 g p4o10 react with 200.0 g h2o ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers