At what temp will a gas be at if you allow it to expand from an original 456 mL to 65°C to 3.4 L

We use the gas law named Charle's law for the calculation of the second temperature. The law states that,

V₁T₂ = V₂T₁

Substituting the known values,

(0.456 L) (65 + 273.15) = (3.4 L) (T₁)

T₁ = 45.33 K