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6 December, 22:08

At what temp will a gas be at if you allow it to expand from an original 456 mL to 65°C to 3.4 L

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  1. 6 December, 22:22
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    We use the gas law named Charle's law for the calculation of the second temperature. The law states that,

    V₁T₂ = V₂T₁

    Substituting the known values,

    (0.456 L) (65 + 273.15) = (3.4 L) (T₁)

    T₁ = 45.33 K
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