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4 January, 03:10

For the aqueous solution containing 75 mg of compound C in 1.0 mL of water, what will be the total amount of the solute C that will be extracted after seven (7) extractions using a certain solvent D if 0.90 mL of a certain organic solvent D was used for each extraction. Given Ksolvent D/water = 1.8.

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  1. 4 January, 03:20
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    75 mg

    Explanation:

    We can write the extraction formula as

    x = m/[1 + (1/K) (Vaq/Vo) ], where

    x = mass extracted

    m = total mass of solute

    K = distribution coefficient

    Vo = volume of organic layer

    Vaq = volume of aqueous layer

    dа ta:

    m = 75 mg

    K = 1.8

    Vo = 0.90 mL

    Vaq = 1.00 mL

    Calculations:

    For each extraction,

    1 + (1/K) (Vaq/Vo) = 1 + (1/1.8) (1.00/0.90) = 1 + 0.62 = 1.62

    x = m/1.62 = 0.618m

    So, 61.8 % of the solute is extracted in each step.

    In other words, 38.2 % of the solute remains.

    Let r = the amount remaining after n extractions. Then

    r = m (0.382) ^n.

    If n = 7,

    r = 75 (0.382) ^7 = 75 * 0.001 18 = 0.088 mg

    m = 75 - 0.088 = 75 mg

    After seven extractions, 75 mg (99.999 %) of the solute will be extracted.
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