Ask Question
30 August, 00:00

Suppose we have a solution of lead nitrate, Pb (NO3) 2 (aq). A solution of NaCl (aq) is added slowly until no further precipitation of PbCl2 (s) occurs. The PbCl2 (s) precipitate is collected by filtration, dried, and weighed. A total of 12.79 grams of PbCl2 (s) is ob - tained from 200.0 milliliters of the original solution. Calculate the molarity of the Pb (NO3) 2 (aq) solution.

+1
Answers (1)
  1. 30 August, 00:24
    0
    0.23 mol/L

    Explanation:

    Step 1:

    The balanced equation for the reaction. This is illustrated below:

    Pb (NO3) 2 (aq) + 2NaCl (aq) - > PbCl2 (s) + 2NaNO3 (aq)

    Step 2:

    Determination of the number of in 12.79g of PbCl2. This is illustrated below:

    Mass of PbCl2 = 12.79g

    Molar Mass of PbCl2 = 207 + (2x35.5) = 207 + 71 = 278g/mol

    Number of mole of PbCl2 = ?

    Number of mole = Mass/Molar Mass

    Number of mole of PbCl2 = 12.79/278

    Number of mole of PbCl2 = 0.046 mole

    Step 3:

    Determination of the number of mole of Pb (NO3) 2 that reacted.

    This is illustrated below:

    From the balanced equation above,

    1 mole of Pb (NO3) 2 reacted to produce 1 mole of PbCl2.

    Therefore, it will also take 0.046 mole of Pb (NO3) 2 to react to produce 0.046 mole of PbCl2.

    Step 4:

    Determination of the molarity of Pb (NO3) 2. This is illustrated:

    Mole of Pb (NO3) 2 = 0.046 mole

    Volume of the solution = 200 mL = 200/1000 = 0.2 L

    Molarity = ?

    Molarity is defined as the mole of solute per unit litre of solution. It is given by:

    Molarity = mole of solute / Volume

    Molarity of Pb (NO3) 2 = 0.046/0.2

    Molarity of Pb (NO3) 2 = 0.23 mol/L
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Suppose we have a solution of lead nitrate, Pb (NO3) 2 (aq). A solution of NaCl (aq) is added slowly until no further precipitation of ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers