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28 March, 21:30

A solution is prepared by mixing 25.0 g H2O and 25.0 g C2H5OH. Determine the mole fractions of each substance.

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Answers (2)
  1. 28 March, 21:39
    0
    Mole fraction H₂O → 0.72

    Mole fraction C₂H₅OH → 0.28

    Explanation:

    By the mass of the two elements in the solution, we determine the moles of each:

    25 g. 1 mol / 18g = 1.39 moles of water (solute)

    25 g. 1 mol / 46 g = 0.543 moles of ethanol (solvent)

    Mole fraction solute = Moles of solute / Total moles

    Mole fraction solvent = Moles of solvent / Total moles

    Total moles = Moles of solute + Moles of solvent

    1.39 moles of solute + 0.543 moles of solvent = 1.933 moles → Total moles

    Mole fraction H₂O = 1.39 / 1.933 → 0.72

    Mole fraction C₂H₅OH = 0.543 / 1.933 → 0.28

    Remember that sum of mole fractions = 1
  2. 28 March, 21:49
    0
    Mol fraction H2O = 0.72

    Mol fraction C2H5OH = 0.28 moles

    Explanation:

    Step 1: Data given

    Mass of H2O = 25.0 grams

    Molar mass H2O = 18.02 g/mol

    Mass of C2H5OH = 25.0 grams

    Molar mass C2H5OH = 46.07 g/mol

    Step 2: Calculate moles

    Moles = mass / molar mass

    Moles H2O = 25.0 grams / 18.02 g/mol

    Moles H2O = 1.39 moles

    Moles C2H5OH = 25.0 grams / 46.07 g/mol

    Moles C2H5OH = 0.54 moles

    Step 3: Calculate total moles

    Total moles = 1.39 moles + 0.54 moles

    Total moles = 1.93 moles

    Step 4: Calculate mol fractions

    Mol fraction = moles / total moles

    Mol fraction H2O = 1.39 moles / 1.93 moles

    Mol fraction H2O = 0.72

    Mol fraction C2H5OH = 0.54 moles / 1.93 moles

    Mol fraction C2H5OH = 0.28 moles
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