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19 April, 12:05

The density of a gas is measured at 1.653 g/L at 746 mmHg and 25.0 °C. What is its molar mass?

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Answers (2)
  1. 19 April, 12:11
    0
    P M = d R T where;

    P: pressure = 746/760 = 0.982 atm

    M : Molar mass (unknown)

    d: density = 1.653 g / L

    R: gas constant = 0.08205 atm. L / mol. K

    T: absolute temperature = 25 + 273 = 298 K

    M = d R T / P

    = (1.653 * 0.08205 * 298) / 0.982 = 41.18 g/mol
  2. 19 April, 12:26
    0
    Given,

    Density of gas = 1.653 g/L

    Pressure = 746 mm Hg = 0.981 atm

    Temperature = 25 degree Celsius or 298 Kelvin

    By ideal gas law we know,

    PV=nRT

    where,

    P=Pressure

    V=Volume of gas

    n = no. of moles

    R=Universal gas constant (0.0821)

    T = temperature

    Now to know the molar mass, we can use following formula;

    Molar mass (M) = mass (m) / no. of moles (n)

    or, No. of moles (n) = mass (m) / Molar mass (M)

    also, density is related to mass by formula;

    Density = Mass (m) * Volume (V)

    o

    Using the above relationship in ideal gas equation, we have,

    P. V = m/M. R. T

    P. V. M = mRT

    M = m / V * RT/P

    Since density = m/V, using the relation we get,

    M = Density * RT/P

    M = (1.653 g/L * 0.082 atm. L/mol. k * 298K) / 0.981 atm

    = 41.22 g/mol

    Hence the molar mass of the gas is 41.22 g/mol
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