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26 August, 15:55

What is the volume of 55 L of gas initially at 500 K and 4.25 atm when conditions change to STP? A. 10.5 L B. 428.1 L C. 584.0 L D. 127.6 L

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Answers (2)
  1. 26 August, 15:57
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    1. 55 L) x (273 K) / (500 K) x (4.25 atm) / (1.00 atm) = 127.6 L

    So answer A.
  2. 26 August, 16:11
    0
    (55 L) x (273 K) / (500 K) x (4.25 atm) / (1.00 atm) = 127.6 L
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