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26 June, 15:06

A container of what volume would be required to store 60.0 moles of a gas at a pressure of 20.0 atm and a temperature of 50.0 Celsius? 12.3 L 79.6 L 8060 L 1250 L

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  1. 26 June, 15:33
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    The answer to your question is: 79.6 L

    Explanation:

    dа ta:

    n = 60 moles

    Pressure = P = 20.0 atm

    Temperature = T = 50°C

    Volume = V = ?

    Convert temperature to Kelvin

    °K = 273 + 50

    °K = 323

    Formula (ideal gas law)

    PV = nRT solve for V

    V = nRT / P

    V = (60) (0.08206) (323) / 20 Substitution

    V = 1590.32 / 20

    V = 79.6 L
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