What volume of a 1.0 M HCl is required to completely neutralize 25.0 ml of a 1.0 M KOH?

Question

Rocco Delgado

Chemistry

5 August, 15:32

What volume of a 1.0 M HCl is required to completely neutralize 25.0 ml of a 1.0 M KOH?

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Answers (1)

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Thalia Hammond · Answer 1

x 0,025

HCl+KOH--> KCl + H2O

1 1

c=1M

V=25ml=0,025l (you need the volume to be in l)

c = n/V

n=c*V

n=1*0,025=0,025 m KOH

x=0,025m

c=1 M

V=n/c

V=0,025/1=0,025l=25ml HCl