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13 February, 01:54

Eugenol is to be isolated using steam distillation. At 100 oC and 744.67 torr calculate the vapor pressure of pure eugenol at 100oC when 16.48% of the distillate collected is eugenol. The vapor pressure of water at 100oC is 760 torr. Put your answer in 5 significant figures.

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  1. 13 February, 02:24
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    Vapor pressure of Eugenol = 667.04torr

    Explanation:

    By applying dalton's law of partial pressure;

    at 100degree celsius, total pressure = 744.67torr

    vapor pressure of water at 100 degree celsius = 760torr

    mole fraction of eugenol = 0.1648

    mole fraction of water = 1 - 0.1648 = 0.8352

    Total pressure = vapor P (water) + vapor P (Eugenol)

    for water; vapour pressure = mole fraction x total pressure

    for eugenol; vapor pressure = mole fraction x total pressure

    substituting into the above gives the vapor pressure of eugenol = 667.04torr
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