When 8 moles of lithium metal react with excess oxygen gas, how many moles of lithium oxide can be produced?

2Li + O2 → Li2O

2

4

8

16

From the balanced equation, we know that one mole of lithium oxide is produced for every two moles of lithium metal. Therefore, we have:

8 moles Lithium * (1 mole Li2O) / (2 moles Lithium) = 4 moles Li2O