A solution containing an ionic compound is subjected to the anion and cation confirmation tests performed in this experiment, providing the following results: Addition of silver nitrate: a bright yellow precipitate formed. Flame test: a purple color was observed. Identify the ionic compound and write the chemical reaction that occurs when the ionic compound interacts with the silver nitrate. Identify the spectator ions.

Question

Cecelia Orozco

Chemistry

23 December, 18:10

A solution containing an ionic compound is subjected to the anion and cation confirmation tests performed in this experiment, providing the following results: Addition of silver nitrate: a bright yellow precipitate formed. Flame test: a purple color was observed. Identify the ionic compound and write the chemical reaction that occurs when the ionic compound interacts with the silver nitrate. Identify the spectator ions.

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Barclay · Answer 1

The spectator ions are K⁺ and NO₃⁻, since these ions do not involve in any reaction.

Explanation:

It is given that a bright yellow precipitate will be formed when the given substance reacts with silver nitrate. Silver nitrate reacts with anion iodide (I⁻) to form yellow precipitate.

In the flame test, if we get purple color then the cation must be Potassium (K⁺).

So if we combine the cation and anion we will get the compound as Potassium Iodide (KI).

K⁺ + I⁻ + Ag⁺ + NO₃⁻ → KNO₃ + AgI (s) ↓

Here Silver and Iodide ions combine to form a precipitate and Potassium and nitrate ions are acting as spectator ions, which do not involve in the reaction.