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3 August, 08:54

How many milliliters of chcl3 are needed to prepare a 2.5% v/v solution in 500 ml of methanol?

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  1. 3 August, 09:20
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    You would need 2.5ml CHCl3 in CH3OH to a final solution volume of 100ml Which is: 2.5*5 = 12.5ml CHCl3 in CH3OH to a final solution volume of 500ml. Be careful: mixing liquids very often means that the volumes are not additive: It is therefore not correct to say: add 12.5ml CHCl3 to 487.5ml CH3OH.
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