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12 November, 17:07

What is the empirical formula for a compound that contains 38.77% Cl and 61.23% O?

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  1. 12 November, 17:11
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    W (Cl) = 0.3877

    w (O) = 0.6123

    M (Cl) = 35.5 g/mol

    M (O) = 16.0 g/mol

    ClₐOₓ

    M (ClₐOₓ) = 35.5a+16.0x

    w (Cl) = 35.5a / (35.5a+16.0x)

    w (O) = 16.0x / (35.5a+16.0x)

    solve a system of two equations with two unknowns

    35.5a / (35.5a+16.0x) = 0.3877

    16.0x / (35.5a+16.0x) = 0.6123

    a=2

    x=7

    Cl₂O₇ is the empirical formula
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