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19 June, 20:32

How calculate how many milliliters of glycerin (specific gravity=1.26) will have a mass of 0.75 lbs?

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  1. 19 June, 21:01
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    Specific gravity is the ratio between the density of the material to the density of water at 4 degrees celcius (density of water at this temperature is 1000 kg/m^3)

    1.26 = density of glycerin / 1000

    density of glycerin = 1260 kg/m^3

    1 Kg is equivalent to 2.2 lbs, therefore:

    0.75 lbs = 0.34 kg

    density = mass/volume

    1260 = 0.34/volume

    volume = 0.34/1260 = 2.857 x 10^-4 m^3

    now, 1 m^3 is equivalent to 1000 liters

    2.857 x 10^-4 m^3 = 0.2857 liters

    one liter is equivalent to 1000 ml

    therefore,

    0.2857 l = 285.7 ml
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