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14 August, 11:10

Calculate the mass of water produced when 2.06 g of butane reacts with excess oxygen.

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  1. 14 August, 11:14
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    2C4H10 + 13O2 = 8CO2 + 10H2O

    1. (2.06g C4H10) / (58.12 g/mol C4H10) = 0.035mol C4H10

    2. (0.035molC4H10) (10 mol H2O/2mol C4H10) = 0.177mol H2O

    3. (0.177mol H2O) (18.01g/mol H2O) = 3.19g H2O
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