Complete the balanced overall ionic equation for sodium iodide dissolving in water.

Sodium Iodide has the following formula: NaI

It dissociates in water forming Na + and I-.

On dissolving NaI in water, Na + part of NaI is attracted to the negative oxygen side of the water molecules, while the l - part is attracted to the positive hydrogens' side of the water molecule.

The ionic equation is as follows:

Nal (solid) + H2O - > Na + (aqueous) + l - (aqueous) + H2O

Answer: NaI (aq) → Na⁺ (aq) + I⁻ (aq)

Explanation:

1) The formula of sodium iodide is NaI

2) Due to the great electronegativities of sodium (Na) and iodine (I), sodium iodide is a ionic compound.

3) Ionic compounds dissociate in water to produce the corresponding ions. In this case, since I has the greatest electronegativity, the ions are Na⁺ and I⁻.

4) When you write the ionic equation, you have to take into account, the number of ions per unit formula and the phases.

So, in this case, the species are in water solutions, this is aqueous solutions. Then you use the symbol aq to indicate the aqueous phase.

The result is the ionic equation: NaI (aq) → Na⁺ (aq) + I⁻ (aq)