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27 June, 14:37

How much heat energy in megajoules is neede to convert 7kilograms of ice at negative 9 degrees to water at 0 degrees celsius

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  1. 27 June, 14:39
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    Heat_1: Get the ice to 0 degrees

    Convert 7 kg to grams

    7 kg [1000 grams / 1 kg] = 7000 grams

    Heat needed to get the the ice from - 9 to 0

    deltat = 0 - - 9 = 9 degrees

    m = 7000 grams

    c = 2.1 joules/gram

    Heat_1 = m*c*deltat

    Heat_1 = 7000 * 2.1 * 9

    Heat_1 = 132,300 joules

    Heat_2: Melt the ice.

    There is no temperature change. The formula is 333 j/gram

    Formula: H = mass * constant

    H = 7000 g * 333 J / gram

    H = 2331000 joules

    Heat_3: Total amount of Joules needed.

    2331000 + 132300 = 2 463 300 joules

    Convert to Megajoules

    2 463 300 joules * 1 megajoule / 1000000 = 2.63 megajoules.
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