B2O3 (s) + 3C (s) + 3Cl2 (g) - - - > 2 BCl3 (g) + 3CO (g)
Calculate how many moles of BCl3 are produced from the reaction of 61.0g of B203?
A. 1.75 mol
B. 0.0150 mol
C. 51.3 mol
D. 211 mol
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