A student must use 220 mL of hot water in a lab procedure. Calculate the amount of heat required to raise the temperature of 220 mL of water from 30.0 / C to 100.0 / C. c for water is 4.184 J/g CC

64,433.6 Joules

Explanation:

We are given;

Volume of water as 220 mL Initial temperature as 30°C Final temperature as 100°C Specific heat capacity of water as 4.184 J/g°C

We are required to calculate the amount of heat required to raise the temperature.

We know that amount of heat is calculated by;

Q = mcΔT, where m is the mass, c is the specific heat, ΔT is the change in temperature.

Density of water is 1 g/mL

Thus, mass of water is 220 g

ΔT = 100°C - 30°C

= 70°C

Therefore;

Amount of heat, Q = 220g * 4.184 J/g°C * 70°C

= 64,433.6 Joules

Thus, the amount of heat required to raise the temperature of water is 64,433.6 Joules