If 27.3 mL of 0.293 M HBr solution completely neutralizes 42.6 mL of NH3, what is the concentration of the NH3 solution? NH3 + HBr yields NH4Br 0.188 M 0.387 M 0.586 M 2.18 M

Question

Lorenzo Conner

Chemistry

11 November, 09:33

If 27.3 mL of 0.293 M HBr solution completely neutralizes 42.6 mL of NH3, what is the concentration of the NH3 solution? NH3 + HBr yields NH4Br 0.188 M 0.387 M 0.586 M 2.18 M

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Brody Lam · Answer 1

According to reaction equation: NH3+HBr=NH4Br, 1 mole of NH3 is required to react with 1 mole of HBr. HBr solution contains 0.0273L * 0.293M = 0.008 moles of HBr. Therefore 0.008 mole of NH3 is reacted. So the concentration of NH3 is 0.008 mole/0.0426 L = 0.188M. The answer is 0.188M.