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29 January, 09:32

A gas evolved during the fermentation of glucose has a volume of 0.78L at 20.1C and 1 atm. What is the volume of this gas if the temperature changes to 40C and 1.2 atm?

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  1. 29 January, 09:52
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    To do this, you need to use the combined gas law

    (P1) (V1) / T (1) = (P2) (V2) / 2

    For temperature, convert to Kelvins

    T1 = 20.1C + 273

    T1 = 293.1 K

    T2 = 40 + 273

    T2 = 313 K

    Now sub the numbers into the formula

    (1) (0.78) / 293.1 = (1.2) (V2) / 313

    0.00266 = 1.2 (V2) / 313

    0.833 = 1.2 (v2)

    V2 = 0.69 L is the new volume
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