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15 August, 12:11

Magnesium sulfate reacts with barium chloride according to the following balanced equation. of 1.20 g of magnesium sulfate is allowed to react with 10.0 g of barium chloride in a water solution, what is the theoretical yield of barium sulfate

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  1. 15 August, 12:25
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    First write the formula and make sure it is balance

    MgSO4 + BaCl2 - - > MgCl2 + BaSO4

    then, we need to determine which reactant is the limiting reagent. using their respective molar masses.

    1.20 g MgSO4 x (1 mole MgSO4 / 120.3 g) = 0.00998 moles

    10.0 g BaCl2 x (1 mole BaCl / 172 g) = 0.0580 moles

    Since MgSO4 give the less amount of moles, MgSO4 is the limiting reagent.

    0.00998 moles MgSO4 (1 mole BaSO4/1 mole MgSO4) (233.3 g / 1 mole BaSO4) = 2.34 grams
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