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4 June, 18:34

What volume of 15.6M NH4OH is needed to make 500. mL of 3.00M solution?

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  1. 4 June, 18:47
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    V₁ = 96.2 mL

    Explanation:

    Given dа ta:

    Initial volume of NH₄OH required = ?

    Initial molarity = 15.6 M

    Final molarity = 3.00 M

    Final volume = 500.0 mL

    Solution:

    Formula:

    M₁V₁ = M₂V₂

    M₁ = Initial molarity

    V₁ = Initial volume of NH₄OH

    M₂ = Final molarity

    V₂ = Final volume

    Now we will put the values.

    15.6 M * V₁ = 3.00 M*500.0 mL

    15.6 M * V₁ = 1500 M. mL

    V₁ = 1500 M. mL / 15.6 M

    V₁ = 96.2 mL
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