8 oz bottle of Dr. Pepper made with imperial cane sugar (C12H22O11) contains 27 g of sugar in 236.6 mL of water. What is the molarity of the solution with respect to cane sugar?

Question

Bear

Chemistry

4 January, 18:44

8 oz bottle of Dr. Pepper made with imperial cane sugar (C12H22O11) contains 27 g of sugar in 236.6 mL of water. What is the molarity of the solution with respect to cane sugar?

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Answers (1)

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Kiley · Answer 1

0.33M

Explanation:

Molarity is asking, in Laymens terms:

"If I took a litre of this stuff, how much stuff is gonna be in it?"

Diving deeper, we use litres instead of millilitres or nanolitres because that's usually what we're working with. We use moles rather than mass because mass varies; different substances have different molar masses, so describing something in g/L makes no sense if you're comparing two different solutions.

Anyway, go find the number of moles:

n=m/mm

n=27g/342.34g/mol

n=0.078870mol

The next question you've gotta ask yourself is:

What if I had a litre of it?

V = 0.2366L

M=n/V

M=0.078870mol/0.2366L

M=0.33M