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29 October, 16:09

Contains 63.65% nitrogen and 36.35% oxygen by mass what is the empirical formula for this compound

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  1. 29 October, 16:17
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    The empirical formula is NO₂.

    Assume that you have 100 g of the compound.

    Then you have 63.65g N and 36.35 g O.

    Now, we must convert these masses to moles and find their ratios.

    From here on, I like to summarize the calculations in a table.

    Element Mass/g Moles Ratio Integers

    N 63.65 4.543 1 1

    O 36.35 2.2719 2.000 2

    The empirical formula is NO₂.
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