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21 August, 00:47

What will be the mass of anhydrous alum left over if one starts with 100.00 g of hydrated alum?

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  1. 21 August, 01:06
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    The formula for hydrated alum is KAl (SO₄) ₂.12H₂O and for anhydrous alum the water molecules are lost. First, we calculate the percentage of water in hydrated alum so that we know how much mass will be lost:

    (12 x 18) x 100 / (474 + 12 x 18)

    = 31.3%

    Therefore, 31.3 grams of water will be lost form the 100 gram sample of hydrated alum and the remaining mass will be 100 - 31.3 = 69.7 grams
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