How many molecules of SO2 are in 2.45 g of SO2? (molar mass=64.06 g/mol). (Hint: you need to use your entire stoichiometry flow chart!)

0.0382 molecules

9.45 x10^25 molecules

2.30 x 10^22 molecules

6.35 x 10^-26 molecules

Question

Stanton

Chemistry

2 August, 22:39

How many molecules of SO2 are in 2.45 g of SO2? (molar mass=64.06 g/mol). (Hint: you need to use your entire stoichiometry flow chart!)

0.0382 molecules

9.45 x10^25 molecules

2.30 x 10^22 molecules

6.35 x 10^-26 molecules

+1

Answers (1)

Know the Answer?

Grace Wilcox · Answer 1

Answer is: 2.30 x 10^22 molecules.

m (SO₂) = 2,45 g - mass of sulfur (IV) - oxide.

M (SO₂) = 64,06 g/mol - molar mass of sulfur (IV) - oxide.

n (SO₂) = m/M = 2,45g : 64,06 g/mol = 0,038 mol - amount of substance

N (SO₂) = n·Na = 0,038 mol · 6,022·10²³ 1/mol = 2,3·10²².

Na - Avogadro number (constant) - 6,022·10²³ 1/mol

How many molecules of SO2 are in 2.45 g of SO2? (molar mass=64.06 g/mol). (Hint: you need to use your entire stoichiometry flow chart!)0.0382 molecules9.45 x10^25 molecules2.30 x 10^22 molecules6.35 x 10^-26 molecules

How many molecules of SO2 are in 2.45 g of SO2? (molar mass=64.06 g/mol). (Hint: you need to use your entire stoichiometry flow chart!)

0.0382 molecules

9.45 x10^25 molecules

2.30 x 10^22 molecules

6.35 x 10^-26 molecules