An aqueous solution has an h3o + concentration of 4.4*10-2 m. calculate [oh-] for this solution.

First calculate Ph

Ph = - log (H3O+)

Ph=-log (4.4 x10^-2) = 1.4

Ph + Poh=14

Poh is therefore = 14 - 1.4=12.6

Oh - concentration is calculated as follows

1 x10^ - POh

that is 1 x10^-12.6 which is = 2.5 x10^-13