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18 August, 08:38

Find the oxidation number of chromium in K2Cr2O7

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  1. 18 August, 08:48
    0
    The oxidation state of chromium is + 6

    Explanation:

    Let the oxidation number be x

    Since The sum of all oxidation numbers are equal to zero,

    So,

    (+1) 2 + 2x + (-2) 7 = 0

    +2 + 2x - 14 = 0

    2x-12 = 0

    2x = + 12

    Dividing 2 to both sides

    x = + 6
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