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28 March, 13:18

Answer the following questions:

If a sample emits 1000 counts per second when the detector is 1 meter from the sample, how many counts per second would be observed when the detector is 2 meters from the sample?

1. Using the sample, how many counts per second would be observed when the detector is 10 meters away from the sample?

2. If Nitrogen-14 absorbs an alpha particle and then emits a Hydrogen-1, what is the resulting nucleus?

3. If Au-185 emits an alpha particle, what is the nucleus formed?

4. What nucleus emits an alpha particle and forms Th-234?

5. If Th-234 emits a beta particle, what nucleus

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Answers (1)
  1. 28 March, 13:40
    0
    The relationship of radiation with distance obeys the inverse square law. Therefore, doubling the distance decrease the radiation by a factor of 4. The new count is 250.

    1) Applying the same principle, the count decreases by a factor of 100. The new count is 10

    2) An alpha particle is 4He2 and the Hydrogen can be represented as 1H1

    14N7 + 4He2 - 1H1

    = 17X8

    Proton number 8 belongs to Oxygen. Therefore, the resultant nucleus is:

    17O8

    3) 185Au79 - 4He2

    = 181Ir77

    4) X - 4He2 = 234Th90

    X = 238U92

    5) Beta emission results in the same nucleon number but an increase in the proton number; therefore, the result is:

    234Pa91
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