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7 July, 06:27

What is the specific heat of an object that weighs 15 G in changes temperature from 30 degrees Celsius to 37 degrees C when 50 joules of heat is added

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  1. 7 July, 06:32
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    c = 0.48 j / g. °C

    Explanation:

    Specific heat capacity:

    It is the amount of heat required to raise the temperature of one gram of substance by one degree.

    Formula:

    Q = m. c. ΔT

    Q = amount of heat absorbed or released

    m = mass of given substance

    c = specific heat capacity of substance

    ΔT = change in temperature

    Given dа ta:

    Mass of object = 15 g

    Change in temperature = 30 °C to 37°C

    Heat absorbed = 50 J

    Specific heat capacity = ?

    Solution:

    ΔT = 37 °C - 30 °C

    ΔT = 7 °C

    Now we will put the values in formula:

    Q = m. c. ΔT

    50 J = 15 g. c. 7 °C

    c = 50 J / 105g. °C

    c = 0.48 j / g. °C
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