What volume (in L) of a 4.13M lithium nitrate solution would be needed to make 195mL of a 1.05M solution by dilution?

0.0496 L

Explanation:

You are diluting the LiNO₃ solution, so you can use the dilution formula.

c₁V₁ = c₂V₂ Divide each side by c₁

V₁ = V₂ * c₂/c₁

c₁ = 4.13 mol·L⁻¹; V₁ = ?

c₂ = 1.05 mol·L⁻¹; V₂ = 195 mL Calculate V₁

V₁ = 195 * 1.05/4.13

V₁ = 195 * 0.2542

V₁ = 49.6 mL Convert to litres

V₁ = 49.6 * 1/1000

V₁ = 0.0496 L