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1 June, 13:38

The compound diborane (b2h6) was at one time considered for use as a rocket fuel. its combustion reaction is b2h6 (g) + 3 o2 (â) â 2 hbo2 (g) + 2 h2o (â) the fact that hbo2, a reactive compound, was produced rather than the relatively inert b2o3 was a factor in the discontinuation of the investigation of the diborane as a fuel. what mass of liquid oxygen (lox) would be needed to burn 106.3 g of b2h6?

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  1. 1 June, 14:04
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    The atomic mas of Oxygen gas is 32 g/mol

    The molar mass of B2H6 IS 27.66 g/mol

    Therefore, a mass of 106.3 g of B2H6 will contain;

    106.3/27.66 = 3.843 moles

    The mole ratio of B2H6 : O2 is 1: 3

    Therefore, moles of oxygen will be 3.843 * 3/1 = 11.529 moles

    Therefore, the mass of liquid oxygen needed would be;

    11.529 * 32

    = 368.94 g
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