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10 June, 16:44

Which equation is set up correctly to determine the volume of a 3.2 mole sample of oxygen gas at 50 degrees celcius and 101.325 kPa

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  1. 10 June, 17:05
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    Ideal gas equation.

    Explanation:

    Given that:

    Pressure = 101.325 kPa

    Also, P (kPa) = 1 / 101.325 atm

    So, pressure = 1 atm

    Temperature = 50°C

    The conversion of T (°C) to T (K) is shown below:

    T (K) = T (°C) + 273.15

    So,

    T = (50 + 273.15) K = 323.15 K

    Volume = ?

    n = 3.2 mole

    Using ideal gas equation as:

    PV=nRT

    where,

    P is the pressure

    V is the volume

    n is the number of moles

    T is the temperature

    R is Gas constant having value = 0.0821 L. atm/K. mol

    Applying the equation as:

    1 atm * V = 3.2 mol * 0.0821 L. atm/K. mol * 323.15 K

    ⇒V = 84.89 L
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