Find the molarity of 750 ml solution containing 346 g of potassium nitrate

Given mass of KNO₃=346g

Molar mass of KNO₃ = (39.098) + (14) + (15.99*3) = 101.068gmol⁻¹

Volume of Solution=750ml=0.75dm³

Molarity = (mass of solute/molar mass of solute) * (1/volume of sol. in dm³)

= (346/101.068) * (1/0.75)

=4.56 mol dm⁻³