What volume of a 0.540 m naoh solution contains 15.5 g of naoh?

The volume of 0.540m NaOH solution that contains 15.5 g of NaOH is calculated as follows

volume = moles/molarity

find moles of NaOH = mass/molar mass

= 15.5 g / 40 g/mol = 0.3875 moles

volume is therefore = 0.3875 / 0.540 = 0.72 Liters

The volume is in liters since molarity in mole per liter