This is the chemical formula for iron (II) hydroxide: Fe (OH) 2 - Calculate the mass percent of hydrogen in iron (II) hydroxide. Round your answer to the nearest percentage.

2.25 % (≈2%) of Fe (OH) 2 are hydrogen atoms

Explanation:

Step 1: Data given

Molar mass of Fe (OH) 2 = 89.86 g/mol

Molar mass of H = 1.01 g/mol

Step 2: Calculate mass % of hydrogen

For 1 molecule Fe (OH) 2 we have 2 hydrogen atoms

Molar mass for 1 hydrogen is 1.01 g/mol, but since we have 2 hydrogen atoms per 1 molecule Fe (OH) 2 is this 2*1.01 = 2.02 g/mol

% = mass of hydrogen atoms / mass of the Fe (OH) 2 molecule

% = (2.02 grams / 89.86 grams) * 100%

% = 2.25 % ≈2

2.25 % (≈2%) of Fe (OH) 2 are hydrogen atoms

2.243%

Explanation:

Molecular weight calculation:

55.845 + (15.9994 + 1.00794) * 2

Molar mass of Fe (OH) 2 = 89.85968 g/mol

Mass percent = molar mass of Hydrogen/molar mass of fe (OH) 2 x 2 mol H/1mol Fe (OH) 2 x 100%

= 1.00794/89.85968 x 100%

= 2.243%