What is E∘cell for a galvanic cell constructed from aluminum and silver electrodes? Report your answer with three decimal places. Half Reaction E∘ (V) Mn2 + (aq) + 2e-⟶Mn (s) - 1.185 Zn (OH) 2 (s) + 2e-⟶Zn (s) + 2OH - (aq) - 1.245 Zn2 + (aq) + 2e-⟶Zn (s) - 0.7618 Al3 + (aq) + 3e-⟶Al (s) - 1.662 Mg2 + (aq) + 2e-⟶Mg (s) - 2.372 Ba2 + (aq) + 2e-⟶Ba (s) - 2.912 K + (aq) + e-⟶K (s) - 2.931 Ag + (aq) + e-⟶Ag (s) + 0.7996 Au3 + (aq) + 3e-⟶Au (s) + 1.498 Provide your answer below:

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Chemistry

25 February, 02:24

What is E∘cell for a galvanic cell constructed from aluminum and silver electrodes? Report your answer with three decimal places. Half Reaction E∘ (V) Mn2 + (aq) + 2e-⟶Mn (s) - 1.185 Zn (OH) 2 (s) + 2e-⟶Zn (s) + 2OH - (aq) - 1.245 Zn2 + (aq) + 2e-⟶Zn (s) - 0.7618 Al3 + (aq) + 3e-⟶Al (s) - 1.662 Mg2 + (aq) + 2e-⟶Mg (s) - 2.372 Ba2 + (aq) + 2e-⟶Ba (s) - 2.912 K + (aq) + e-⟶K (s) - 2.931 Ag + (aq) + e-⟶Ag (s) + 0.7996 Au3 + (aq) + 3e-⟶Au (s) + 1.498 Provide your answer below:

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Garfield · Answer 1

When the galvanic cell is formed with the electrode Al and Ag, following half cell reaction is possible

Al = Al⁺³ + 3e (At anode)

3Ag⁺ + 3e = 3Ag. (At cathode)

Ecell = Ecathode - Eanode

=.7996 - ( - 1.662) [ values taken from the chart given ]

=.7996 + 1.662

= 2.4616

= 2.462 V.